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In the given circuit as shown in figure, in the steady state, obtain the expression for (i) potential drop (ii) the charge and (iii) the energy stored in the capacitor C. |
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Answer» In the steady state, the capacitor C is the fully charged. So no current flows through the arm BE of the circuit. `:.` Effective emf of the circuit `= 2V- V=V` Effective resistance of the circuit `= 2 R +R = 3R` Current in the circuit, `I= (V)/(3R)` Potential difference between across B and E `= 2 V - I xx 2R= 2V - (V)/(3R) xx 2R = 4/3 V` (i) potential difference across C `=4/3 V - V= V/3` (ii) Charege on capacitor `Q= CV = C xx V/3 = (CV)/(3)` (iii) Energy stored in the capacitor `=1/2 C(V/3)^(2)= (CV^(2))/(18)` |
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