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In the given circuit current flowing through the resistance `20Omega` is `0.3A,` while the ammeter reads 0.8 A. What is the value of `R_1` A. `30 Omega`B. `40 Omega`C. `50 Omega`D. `60 Omega` |
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Answer» Correct Answer - D `V_(20Omega)=V_(Total)` `:. (20)(0.3)=(R_(Total))(0.8)` `: R_(Total)=30/4Omega` `:. 4/30=1/R_1+1/20+1/15` Solving we get `R_1=60Omega` |
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