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In the given circuit the voltage drop across the diode is 0.8 V, if the diode can withstand current upto maximum of 30 mA, then find the maximum voltage of the battery |
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Answer» Let V is the maximum forward biased voltage then , `V=lR+V_(D)` `V=30xx10^(-3) xx500+0.8` `V=15+0.8` V=15.8V |
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