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In the given cyclic process from c to b 40 J heat is exchanged from b to a 130 J heat is exchanged and work done is 80 J from a to c, 400 J heat is exchanged, then: A. Work done in process a to c is 310 JB. Net work done in cycle is 230 JC. Net change in internal energy in cycle is 130 JD. Efficiency of cycle `57.5%` |
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Answer» Correct Answer - A::B::D `DeltaU_(cycl e)=0` `Q_(n et)=W_(n et)` `-40-130+400=W_(cb)+W_(ba)+W_(ac)` `230=0+(-80J)+W_(ac)` `W_(ac)=310J` `Thermal efficiency = (Work output)/(Heat input)` `=230/400xx100=11.5xx5=57.5` |
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