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In the given detector circuit, the suitable value of carrier frequency is A. `ltlt10^(9)Hz`B. `ltlt10^(5)Hz`C. `gtgt10^(9)Hz`D. None of these |
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Answer» Correct Answer - a Using `(1)/(f_("carrier"))ltltRC` we get time constant, `RC=1000xx10^(-12)=10^(-9)s` Now `v=(1)/(T)=(1)/(10^(-9))=10^(9)Hz` Thus the value of carrier frequency should be much less than `10^(9)Hz`, say `100 kHz`. |
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