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In the given fig O is centre of circle, `/_ACO =35^@`and `/_ABO =45^@`, then what is the value of `/_BOC` |
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Answer» from the given figure we can conclude that `/_ BAC = 45^@ + 35^@` `= 80^@` Now as we can see that `/_ BOC = 2/_BAC` `/_BOC = 2 xx 80^@` `= 160^@` Answer |
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