1.

In the given figure, A, B, C and D are four points on a circle. AC and BD intersect at a point E such that ∠BEC = 130° and ∠ECD = 20°. Find ∠BAC.

Answer» In ΔCDE,

∠CDE + ∠DCE = ∠CEB (Exterior angle)

∠CDE + 20° = 130°

∠CDE = 110°

However, ∠BAC = ∠CDE (Angles in the same segment of a circle)

∠BAC = 110°


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