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In the given figure, a parallelogram ABCD and a rectangle ABEF are of equal area. Then,(a) perimeter of ABCD = perimeter of ABEF(b) perimeter of ABCD < perimeter of ABEF(c) perimeter of ABCD > perimeter of ABEF(d) perimeter of ABCD = 12 perimeter of ABEF |
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Answer» In the given figure, a parallelogram ABCD and a rectangle ABEF are of equal area. Then, (a) perimeter of ABCD = perimeter of ABEF (b) perimeter of ABCD < perimeter of ABEF (c) perimeter of ABCD > perimeter of ABEF (d) perimeter of ABCD = perimeter of ABEF
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