In the given figure, a tent is in the shape ofa cylinder surmounted by

1.	In the given figure, a tent is in the shape ofa cylinder surmounted by a conical top ofsame diameter. If the height and diameter ofcylindrical part are 2.1 m and 3 m respectivelyand the slant height of conical part is 2.8 m, findthe cost of canvas needed to make the tent if thecanvas is available at the rate of 500 per sqmetre. Use T-[O.D. Set I, II, III, 2016]
Answer» Height (h) of the cylindrical part = 2.1 m Diameter of the cylindrical part = 3 m Radius of the cylindrical part = 3/2 m Slant height (l) of conical part = 2.8 m Total canvas used = CSA of conical part + CSA of cylindrical part = πrl + 2πrh = πr(2h+l) = (22/7)×3/2(2×2.1+2.8) = (22/7)×3/2(4.2+2.8) = (22/7)×3/2(7) = 11×3 = 33 m² Cost of 1 m² canvas = ₹ 500 Cost of 44 m² canvas = 33 × 500 = 16500 The cost of Canvas needed to make the tent= ₹ 16500 Hence, it will cost ₹ 16500 for making such a tent. right thanks

In the given figure, a tent is in the shape ofa cylinder surmounted by a conical top ofsame diameter. If the height and diameter ofcylindrical part are 2.1 m and 3 m respectivelyand the slant height of conical part is 2.8 m, findthe cost of canvas needed to make the tent if thecanvas is available at the rate of 500 per sqmetre. Use T-[O.D. Set I, II, III, 2016]

Answer»

Height (h) of the cylindrical part = 2.1 m

Diameter of the cylindrical part = 3 m

Radius of the cylindrical part = 3/2 m

Slant height (l) of conical part = 2.8 m

Total canvas used = CSA of conical part + CSA of cylindrical part

= πrl + 2πrh

= πr(2h+l)

= (22/7)×3/2(2×2.1+2.8)

= (22/7)×3/2(4.2+2.8)

= (22/7)×3/2(7)

= 11×3

= 33 m²

Cost of 1 m² canvas = ₹ 500

Cost of 44 m² canvas = 33 × 500 = 16500

The cost of Canvas needed to make the tent= ₹ 16500

Hence, it will cost ₹ 16500 for making such a tent.

right thanks