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In the given figure, AB and AC are tangents to the circle with centre O.Given that ∠BAC= 70° and P is a point on the minor arc BC, find ∠BPC.(a) 110° (b) 140° (c) 125° (d) 136° |
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Answer» (c) 125° ∠AOB + ∠APB=180° (The angle between two tangents drawn from an external pt. to a circle is supplementary to the angle subtended by the line segments joining the points of contact at the centre) ⇒ ∠AOB= 180° – 70°= 110° Reflex ∠AOB= 360° – 110° = 250° ∴ ∠BPC = \(\frac{1}{2}\)× Reflex ∠AOB = \(\frac{1}{2}\) × 250° = 125° |
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