In the given figure, AB BC, M is mid-point of AB and N is mid-print of

1.	In the given figure, AB BC, M is mid-point of AB and N is mid-print of BC. Using Euclid'saxioms, prove that AM = NC.
Answer» Given : AB = BC .....(1) MB = NB .....(2) ( due to midpoint) So, Eq(1) - Eq(2) AB - MB = BC - NB AM = NC ( proved) Third Axiom: If equals be subtracted from equals, the remainders are equal

In the given figure, AB BC, M is mid-point of AB and N is mid-print of BC. Using Euclid'saxioms, prove that AM = NC.

Answer»

Given :

AB = BC .....(1)

MB = NB .....(2) ( due to midpoint)

So,

Eq(1) - Eq(2)

AB - MB = BC - NB

AM = NC ( proved)

Third Axiom: If equals be subtracted from equals, the remainders are equal