InterviewSolution
Saved Bookmarks
| 1. |
In the given figure, AB is diameter of a circle with centre O and AT is a tangent at `angleAOQ=58^@`, find `angleATQ`. |
|
Answer» `/_ATQ=?` `/_ABT=1/2/_AOQ` `/_ABT=1/2xx58^@` `=29^@` `/_ABT=29^@` In`/_ABT` `/_A+/_B+/_T=180^@` `90+29+/_T=180^@` `/_T=180-119` `=61^@` `/_ATQ=61^@` |
|