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In the given figure, ∠ABC = 90° and BD⊥AC. If BD = 8cm, AD = 4cm, find CD. |
Answer» It is given that ABC is a right angled triangle and BD is the altitude drawn from the right angle to the hypotenuse. In ∆ DBA and ∆ DCB, we have : ∠BDA = ∠CDB ∠DBA = ∠DCB = 90° Therefore, by AA similarity theorem, we get : ∆DBA - ∆ DCB ⇒ BD/CD = AD/BD ⇒ CD = BD2/AD CD = 8×8/4 = 16 cm |
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