InterviewSolution
Saved Bookmarks
| 1. |
In the given figure, ABC and AED are straight lines. AB is the diameter of the smaller circle ABE. Find the measure of `/_ACD`. |
|
Answer» As `AB` is the diameter of the smaller circle, `:. /_AEB = 90^@` As, `AED` is a straight line, `:. /_AEB+/_DEB = 180^@` `=>/_DEB = 180^@ - 90^@ = 90^@` Now, `BEDC` is a cyclic quadrilateral. `:. /_DEB+/_BCD = 180^@` `=>90^@+/_BCD = 180^@` `=>/_BCD = 90^@` Also, `/_ACD = /_BCD` `:. /_ACD = 90^@` |
|