1.

In the given figure, ABC and AED are straight lines. AB is the diameter of the smaller circle ABE. Find the measure of `/_ACD`.

Answer» As `AB` is the diameter of the smaller circle,
`:. /_AEB = 90^@`
As, `AED` is a straight line,
`:. /_AEB+/_DEB = 180^@`
`=>/_DEB = 180^@ - 90^@ = 90^@`
Now, `BEDC` is a cyclic quadrilateral.
`:. /_DEB+/_BCD = 180^@`
`=>90^@+/_BCD = 180^@`
`=>/_BCD = 90^@`
Also, `/_ACD = /_BCD`
`:. /_ACD = 90^@`


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