In the given figure, ABCD is a ||gm and E is the midpoint of BC. Also,

1.	In the given figure, ABCD is a \|\|gm and E is the midpoint of BC. Also, DE and All when produced meet at F. Then, (a) AF=32AB (b) AF = 2AB (c) AF = 3AB (d) AF2=2AB2
Answer» In the given figure, ABCD is a \|\|gm and E is the midpoint of BC. Also, DE and All when produced meet at F. Then, (a) $A F = \frac{3}{2} A B$ (b) AF = 2AB (c) AF = 3AB (d) $A F^{2} = 2 A B^{2}$

In the given figure, ABCD is a ||gm and E is the midpoint of BC. Also, DE and All when produced meet at F. Then, (a) AF=32AB (b) AF = 2AB (c) AF = 3AB (d) AF2=2AB2

Answer»

In the given figure, ABCD is a ||gm and E is the midpoint of BC. Also, DE and All when produced meet at F. Then,

(a) $A F = \frac{3}{2} A B$

(b) AF = 2AB

(d) $A F^{2} = 2 A B^{2}$