In the given figure, ABCD is a parallelogram and PD is parallel to QC.

1.	In the given figure, ABCD is a parallelogram and PD is parallel to QC. S1 : △APD≅△BQC S2 : ar(△APD)+ ar(PBCD)= ar(△BQC)+ ar(CDPB)
Answer» In the given figure, $A B C D$ is a parallelogram and $P D$ is parallel to $Q C .$ S1 : $△ A P D ≅ △ B Q C$ S2 : ar( $△ A P D) +$ ar( $P B C D) =$ ar( $△ B Q C) +$ ar $(C D P B)$

In the given figure, ABCD is a parallelogram and PD is parallel to QC. S1 : △APD≅△BQC S2 : ar(△APD)+ ar(PBCD)= ar(△BQC)+ ar(CDPB)

Answer»

In the given figure, $A B C D$ is a parallelogram and $P D$ is parallel to $Q C .$

S1 : $△ A P D ≅ △ B Q C$

S2 : ar( $△ A P D) +$ ar( $P B C D) =$ ar( $△ B Q C) +$ ar $(C D P B)$