In the given figure, ABCD is a parallelogram and PD is parallel to QC.

1.	In the given figure, ABCD is a parallelogram and PD is parallel to QC. S1 : △APD ≅ △BQC S2 : ar(△APD) + ar(PBCD) = ar(△BQC) + ar(CDPB)
Answer» In the given figure, ABCD is a parallelogram and PD is parallel to QC. S1 : $△$ APD $≅$ $△$ BQC S2 : ar( $△$ APD) + ar(PBCD) = ar( $△$ BQC) + ar(CDPB)

In the given figure, ABCD is a parallelogram and PD is parallel to QC. S1 : △APD ≅ △BQC S2 : ar(△APD) + ar(PBCD) = ar(△BQC) + ar(CDPB)

Answer»

S1 : $△$ APD $≅$ $△$ BQC

S2 : ar( $△$ APD) + ar(PBCD) = ar( $△$ BQC) + ar(CDPB)