1.

In the given figure, AD = 2cm, BD = 3 cm, AE = 3.5 cm and AC = 7 cm. Is DE parallel to BC ?

Answer»

EC = AC – AE = (7 - 3.5)cm = 3.5 cm 

\(\frac{AD}{BD}\) = \(\frac{2}{3}\) and \(\frac{AE}{EC}\) = \(\frac{3.5}{3.5}\) = \(\frac{1}{1}\)

So, \(\frac{AD}{BD}\) ≠ \(\frac{AE}{EC}\)

Hence, By converse of Thale’s Theorem, DE is not Parallel to BC.



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