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In the given figure, AD = AE and `AD^2 = BD xx EC` prove that: triangles ABD and CAE are similar. |
Answer» AD=AE `/_ADE=/_AED` `/_ADB=/_AEC` `AD^2=BD*EC` `(AD)/(BD)=(EC)/(AD)` `(AD)/(BD)=(EC)/(AE)` `In/_ABD and /_CAE` `(AD)/(BD)=(EC)/(AE)` `/_ADB=/_AEC` `/_ABD cong /_CAE`. |
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