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In the given figure, AD and AE are the tangents to a circle with centre O and BC touches the circle at F. If AE = 5 cm, then perimeter of △ABC is(a) l5cm (b) 10cm (c) 22.5 cm (d) 20cm |
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Answer» Correct answer is (b) 10 cm Since the tangents from an external point are equal, we have AD = AE, CD = CF, BE = BF Perimeter of △ABC = AC + AB + CB = (AD - CD) + (CF + BF) + (AE - BE) = (AD - CF) + (CF + BF) + (AE - BF) = AD + AE = 2AE = 2 x 5 = 10 cm |
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