1.

In the given figure, AD and AE are the tangents to a circle with centre O and BC touches the circle at F. If AE = 5 cm, then perimeter of △ABC is(a) l5cm (b) 10cm (c) 22.5 cm (d) 20cm

Answer»

Correct answer is (b) 10 cm

Since the tangents from an external point are equal, we have

AD = AE, CD = CF, BE = BF

Perimeter of △ABC = AC + AB + CB

= (AD - CD) + (CF + BF) + (AE - BE)

= (AD - CF) + (CF + BF) + (AE - BF)

= AD + AE

= 2AE

= 2 x 5

= 10 cm



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