In the given figure, AL is parallel to DC and E Is mid point of BC. Sh – InterviewSolution

InterviewSolution

1.

In the given figure, AL is parallel to DC and E Is mid point of BC. Show that triangle EBL Is congruent to triangle ECD.

Answer»

From the adjacent figure

AL // CD and E is the midpoint of BC.

i.e., BE = EC

from ΔBEL & ΔCED.

∠B = ∠C [ ∵ Alternate interior angles]

∠DEC = ∠BEL [ ∵ vertically opposite, angles]

∴ By A.S.A rule

Δ EBL ≅ Δ ECD.

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