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In the given figure, angle BTO=30°. Find angleATO, where O is centre of circle and TA and TB are tangents. |
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Answer» In ∆ AOT and ∆BOTAO = BOangle A = angle B (90°)OT = OT ( common)So, by RHS rule ∆ AOT and ∆BOT are congurent.So, by CPCT angle BTO = angle OTAangle ATO = 30° |
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