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In the given figure common tangents AB and CD to the two circles with centres O1 and O2 intersect at E. Prove that AB = CD. |
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Answer» We know that tangent segments to a circle from the same external point are congruent. So, we have EA = EC for the circle having center O1 and ED = EB for the circle having center O1 Now, Adding ED on both sides in EA = EC. we get EA + ED = EC + ED \(\Rightarrow\) EA + EB = EC + ED \(\Rightarrow\) AB = CD |
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