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In the given figure, `Delta ODC~ Delta OBA, angle BOC =115^(@) and angle COD =70^(@)` Find (i) `angle DOC (ii) angle DCO (iii) angle OAB (iv) angle OBA` |
Answer» Correct Answer - `(i) angle DOC=65^(@) " " (ii) angle DCO=45^(@) " " (iii) angle OAB=45^(@) " " (iv) angle OBA=70^(@)` `angle DOC=(180^(@)-115^(@))=65^(@), angle DCO=180^(@)-(70^(@)+65^(@))=45^(@)` `Delta ODC~ Delta OBA rArr angle OAB= angle DCO=45^(@), angle OBA= angle ODC=70^(@)` |
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