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In the given figure, `Delta OQP~ Delta OAB, angle OPQ =56^(@) and angle BOQ=132^(@)`. Find `angleOAB`. |
Answer» In `Delta OPQ`, we have `angle BOQ= angle OPQ+angle OQP` [ `:.` the exterior angle is equal to the sum of the two interior opposite angles ] `rArr angle OQP= angle BOQ- angle OPQ =132^(@)=132^(@)-56^(@)=76^(@)`, Now, `Delta OQP~ Delta OAB` `rArr angle OQP= angle OAB` [ corresponding angles of similar triangles] `:. angleOAB= angle OQP=76^(@)` |
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