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In the given figure, G is the centroid of ∆ ABC, such that GD = 3 cm and BC = 4 cm. Then find the area of ∆ ABC. |
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Answer» In ∆ GBC, BC = 4 cm and GD = 3 cm. area (∆ GBC) = (1/2) x Base x Altitude = (1/2) x 4 x 3 = 6 cm2 ar (∆ ABC) = 3 x ar (∆ GBC) = 3 x 6 cm2 ar (∆ ABC) = 18 cm2 |
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