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In the given figure, if AB=AC, rove that BE=EC. |
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Answer» We know that, length of tangents from an external point are equal. `:." "AD=AF" "…(1)` `DB=BE" "…(2)` `EC=FC" "…(3)` Now, it is given that `AB=AC` `implies" "AD+DB=AF+FC` `implies" "cancel(AD)+DB=cancel(AD)+EC" "`[from (1)and(3)] `implies" "DB=EC` `:." "BE=EC" "`[from (2), DB=BE] Hence Proved. |
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