1.

In the given figure if AD ⊥ BC, prove that AB2 + CD2 = BD2 + AC2. 

Answer»

Given: In △ABC, AD ⊥ BC. 

R.T.P: AB2 + CD2 = BD2 + AC2 

Proof: △ABD is a right angled triangle 

AB2 – BD2 = AD2 ……. (1) 

△ACD is a right angle triangle

AC2 – CD2 = AD2............ (2) 

From (1) and (2) 

AB2 – BD2 = AC2 – CD2 

AB2 + CD2 = BD2 + AC2



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