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In the given figure if AD ⊥ BC, prove that AB2 + CD2 = BD2 + AC2. |
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Answer» Given: In △ABC, AD ⊥ BC. R.T.P: AB2 + CD2 = BD2 + AC2 Proof: △ABD is a right angled triangle AB2 – BD2 = AD2 ……. (1) △ACD is a right angle triangle AC2 – CD2 = AD2............ (2) From (1) and (2) AB2 – BD2 = AC2 – CD2 AB2 + CD2 = BD2 + AC2 |
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