Saved Bookmarks
| 1. |
In the given figure if AD = DC = BC and ∠BCE=96∘ then ∠DBC is |
|
Answer» Given:- AD = CD = BC Sol:- Since, AD = CD = BC so, ∠CAD = DCA and ∠CDB = ∠DBC Let ∠CAD be x° and ∠CDB be y° In ∆CAD, by exterior angle property y = 2x ∴ x = y/2 -- (1) In ∆CAB, by exterior angle property, x + y = 96° ⇒ y/2 + y = 96° (From 1) ⇒ 3y/2 = 96° ∴ y = 32 × 2 = 64° Therefore, ∠DBC is 64° |
|