1.

In the given figure if `angle DBC =70^@` and `angle BAC =40^@` then find the value of `angle BCD`

Answer» We know, angle made by a common chord at any point of circle are always equal.
`:. /_BAC = /_BDC = 40^@`
Now, in `Delta BDC`,
`/_DBC+/_BDC+/_BCD = 180^@`
`=>70^@+40^@+/_BCD = 180^@`
`/_BCD = 180^@-110^@ = 70^@`


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