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In the given figure if `angle DBC =70^@` and `angle BAC =40^@` then find the value of `angle BCD` |
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Answer» We know, angle made by a common chord at any point of circle are always equal. `:. /_BAC = /_BDC = 40^@` Now, in `Delta BDC`, `/_DBC+/_BDC+/_BCD = 180^@` `=>70^@+40^@+/_BCD = 180^@` `/_BCD = 180^@-110^@ = 70^@` |
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