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In the given figure, it is given that AB = AC; ∠BAC = 36°; ∠ADB = 45° and ∠AEC = 40°. Find ∠DAB |
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Answer» Given that AB = AC; ∠BAC = 36°, ∠ADB = 45°, ∠AEC = 40° From the figure ∠ABD + ∠ABC = 180° ∠ABD = 180° – 72° = 1086 In ΔABD ∠DAB + ∠ABD + ∠D = 180° ∠DAB + 108° + 45° = 180° ∠DAB = 180° – 153° = 27° |
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