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In the given figure, m and n are two plane mirrors perpendicular to each other. Show that the incident ray CA is parallel to the reflected ray BD. |
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Answer» Let the normals at A and B meet at P. Since angle of incidence = angle of reflection, we have `angle1=angle2 and angle4=angle3` As the mirrors are perpendicular to each other, we have `BP bot PA`, we have `angleAPB=90^(@)`. `:. angle2+angle3=90^(@)` `:. angle1+angle4=angle2+angle3=90^(@)`. So, `angle1+angle2+angle3+angle4=180^(@)`. `:. angleCAB+angleABD=180^(@)`. Hence, `AC||BD`. |
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