1.

In the given figure, m and n are two plane mirrors perpendicular to each other. Show that the incident ray CA is parallel to the reflected ray BD.

Answer» Let the normals at A and B meet at P.
Since angle of incidence = angle of reflection, we have
`angle1=angle2 and angle4=angle3`
As the mirrors are perpendicular to each other, we have
`BP bot PA`, we have `angleAPB=90^(@)`.
`:. angle2+angle3=90^(@)`
`:. angle1+angle4=angle2+angle3=90^(@)`.
So, `angle1+angle2+angle3+angle4=180^(@)`.
`:. angleCAB+angleABD=180^(@)`.
Hence, `AC||BD`.


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