In the given figure, m1=200 g, m2=600 g,μ1=0.3, μ2=0.8 and K=200 N/m.The minimum force that must be applied on m1 to just displace m2 is (in N). (Take g = 10 m/s2)

In the given figure, m1=200 g, m2=600 g,μ1=0.3, μ2=0.8 and K=200 N

1.	In the given figure, m1=200 g, m2=600 g,μ1=0.3, μ2=0.8 and K=200 N/m.The minimum force that must be applied on m1 to just displace m2 is (in N). (Take g = 10 m/s2)
Answer» In the given figure, $m_{1} = 200 g,$ $m_{2} = 600 g,$ $μ_{1} = 0.3,$ $μ_{2} = 0.8$ $a n d K = 200 N / m .$ The minimum force that must be applied on $m_{1}$ to just displace $m_{2}$ is (in N). (Take g = 10 m/ $s^{2}$ )

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In the given figure, m1=200 g, m2=600 g,μ1=0.3, μ2=0.8 and K=200 N/m.The minimum force that must be applied on m1 to just displace m2 is (in N). (Take g = 10 m/s2)

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