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In the given figure, O is the centre of a circle. PT and PQ are tangents to the circle from an external point P. If ∠TPQ = 70°, find ∠TRQ. |
Answer» Here, O is the centre of circle. PQ and PT are tangents to the circle from a point P R is any point on the circle. RT and RQ are joined. ∠TPQ = 70° Now, Join TO and QO. ∠TOQ = 180° – 70° = 110° Here, OQ and OT are perpendicular on QP and TP. ∠TOQ is on the centre and ∠TRQ is on the rest part. ∠TRQ = 1/2∠TOQ = ½( 110°) = 55° Therefore, ∠TRQ = 55°. |
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