1.

In the given figure, O is the centre of a circle such that OA = 5 cm, AB = 8 cm and `OD_|_AB` meeting AB at C. Find the length of CD.

Answer» As `OD _|_ AB`,
`:. AC = 1/2AB = 1/2*8 = 4cm`
Here, `OA = OD = 5cm`
`:. OC = sqrt(OA^2-AC^2) = sqrt(5^2-4^2) = 3cm`
Now, `CD = OD - OC = 5-3 = 2cm`


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