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In the given figure, O is the centre of the circle, ∠ACB = 54° and BCE is a straight line. Find x.(a) 126° (b) 54° (c) 108° (d) 90° |
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Answer» (c) 108° ∠ACE = 180° – 54° = 126° (BCE is a straight line) ⇒ ∠ADE = ∠ACE = 126° (Angles in the same segement are equal) ∴ Reflex ∠AOE = 2 × ∠ADE = 2 × 126° = 252° (Angle at the centre = 2 × Angle at any other pt. on remaining part of the circle) ∴ x = 360° – 252° = 108°. |
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