1.

In the given figure, O is the centre of the circle. If ∠ABD = 35° and ∠BAC = 70°, find ∠ACB.

Answer»

We know that BD is the diameter of the circle

Angle in a semicircle is a right angle

∠BAD = 90o

Consider △ BAD

Using the angle sum property

∠ADB + ∠BAD + ∠ABD = 180o

By substituting the values

∠ADB + 90o + 35o = 180o

On further calculation

∠ADB = 180o – 90o – 35o

By subtraction

∠ADB = 180o – 125o

So we get

∠ADB = 55o

We know that the angles in the same segment of a circle are equal

∠ACB = ∠ADB = 55o

So we get

∠ACB = 55o

Therefore, ∠ACB = 55o.



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