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In the given figure, O is the centre of the circle. If ∠ABD = 35° and ∠BAC = 70°, find ∠ACB. |
Answer» We know that BD is the diameter of the circle Angle in a semicircle is a right angle ∠BAD = 90o Consider △ BAD Using the angle sum property ∠ADB + ∠BAD + ∠ABD = 180o By substituting the values ∠ADB + 90o + 35o = 180o On further calculation ∠ADB = 180o – 90o – 35o By subtraction ∠ADB = 180o – 125o So we get ∠ADB = 55o We know that the angles in the same segment of a circle are equal ∠ACB = ∠ADB = 55o So we get ∠ACB = 55o Therefore, ∠ACB = 55o. |
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