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In the given figure, ‘O’ is the centre of the circle and AB, CD are equal chords. If ∠AOB = 70°. Find the angles of ΔOCD. |
Answer» ‘O’ is the centre of the circle. AB, CD are equal chords ⇒ They subtend equal angles at the centre. ∴ ∠AOB =∠COD = 70° Now in ΔOCD ∠OCD = ∠ODC [∵ OC = OD; radii angles opp. to equal sides] ∴ ∠OCD + ∠ODC + 70° = 180° = ∠OCD +∠ODC = 180° – 70° = 110° ∴ ∠OCD + ∠ODC = 110° = 55° |
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