1.

In the given figure, O is the centre of the circle and BA = AC. If `angleABC=50^@`, find `angleBOC` and `angleBDC.`

Answer» BA=AC
`/_ABC=/_ACB`
`50^@=/_ACB`
`In/_ABC`
`/_A+/_B+/_C=180^@`
`/_A+50+50=180`
`/_A=80^@`
`/_BOC=2/_A`
`/_BOC=2*80=160^@`
`/_BAC+/_BDC=180`
`80+/_BDC=180`
`/_BDC=100`.


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