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In the given figure, ∆OAB ~ ∆OCD. If AB = 8cm, BO = 6.4cm, OC = 3.5cm and CD = 5cm, find (i) OA (ii) DO. |
Answer» (i) Let OA be X cm. ∵ ∆ OAB - ∆ OCD ∴ OA/ OC = AB/CD ⇒ X/3.5 = 8/5 ⇒ X = 8×3.5/5 = 5.6 Hence, OA = 5.6 cm (ii) Let OD be Y cm ∵ ∆ OAB - ∆ OCD ∴ AB/CD = OB/OD ⇒ 8/5 = 6.4/Y ⇒ Y = 6.4 ×5/8 = 4 Hence, DO = 4 cm |
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