1.

In the given figure, PQ is a chord of a circle with centre O and PT is a tangent. If `/_QPT=60^@` find `/_PRQ`

Answer» In the given figure,
`/_QPT = 60^@`
`/_QPO = /_OPT-/_QPT = 90-60 = 30^@`
As, `OP = OQ`,
`:. /_OPQ =/_OQP = 30^@`
`:. /_POQ = 180-30-30 = 120^@`
Now, `/_PRQ = 1/2(360-/_POQ) = 240/2 = 120^@`


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