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In the given figure, PS is a straight line, find x°. |
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Answer» From the given figure, ∠POQ = 60° ∠QOR = x° ∠ROS = 47° But ∠POQ + ∠QOR + ∠ROS = 180° ⇒ 60° + x° + 47° = 180° ⇒ x° + 107° = 180° ⇒ x° = 180°- 107° ∴ x° = 73° |
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