1.

In the given figure, PS is a straight line, find x°.

Answer»

From the given figure, ∠POQ = 60° 

∠QOR = x° 

∠ROS = 47° But 

∠POQ + ∠QOR + ∠ROS = 180° 

⇒ 60° + x° + 47° = 180° 

⇒ x° + 107° = 180° 

⇒ x° = 180°- 107°

∴ x° = 73°



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