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In the given figure, quad. ABCD is circumscribed touching the circle at P, Q, R and S. If AP = 5 cm, BC= 7 c m and CS = 3 cm. Then, the length of AB = ?(a) 9 cm (b) 10 cm (c) 12 cm (d) 8 cm |
Answer» Correct answer is (a) 9 cm Tangents drawn from an external point to a circle are equal. So, AQ = AP = cm CR = CS = 3cm And BR = (BC - CR) \(\Rightarrow\) BR = (7 - 3)cm \(\Rightarrow\) BR = 4cm BQ = BR = 4cm ∴ AB = (AQ + BQ) \(\Rightarrow\) AB = (5 + 4)cm \(\Rightarrow\) AB = 9cm |
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