In the given figure, the area of cross-section of B is 10 times greate

1.	In the given figure, the area of cross-section of B is 10 times greater than that of A(a) What is the working principle behind this device? (b) If a force of 20 N is applied on A, what will be the force experienced on B? (c) If the section A is lowered by 1 cm, how much will B rise up?
Answer» (a) Pascal’s law (b) \(\frac{A_B}{A_A}=10\) F_A= 20 N \(\frac{F_B}{F_A}=\frac{A_B}{A_A}\) \(\frac{F_B}{20}=10\) F_B = 20 x 10 = 200 N (c) Rises 10 cm

In the given figure, the area of cross-section of B is 10 times greater than that of A(a) What is the working principle behind this device? (b) If a force of 20 N is applied on A, what will be the force experienced on B? (c) If the section A is lowered by 1 cm, how much will B rise up?

Answer»

(a) Pascal’s law

(b) \(\frac{A_B}{A_A}=10\)

F_A= 20 N

\(\frac{F_B}{F_A}=\frac{A_B}{A_A}\)

\(\frac{F_B}{20}=10\)

F_B = 20 x 10 = 200 N