1.

In the given figure, the point P bisects AB and DC. Prove that ΔAPC ≅ ΔBPD.

Answer»

Given that P bisects AB and DC. 

Now in ΔAPC and ΔBPD 

AP = BP (∵ P bisects AB) 

CP = DP (∵ P bisects CD)

∠ APC = ∠ BPD 

∴ ΔAPC ≅ ΔRPP (∵ SAS congruence)



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