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In the given figure, the point P bisects AB and DC. Prove that ΔAPC ≅ ΔBPD. |
Answer» Given that P bisects AB and DC. Now in ΔAPC and ΔBPD AP = BP (∵ P bisects AB) CP = DP (∵ P bisects CD) ∠ APC = ∠ BPD ∴ ΔAPC ≅ ΔRPP (∵ SAS congruence) |
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