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In the given figure the tension in the stiring OB is 30N. Find the weight .W. and the tension in the string OA. |
Answer» Solution :Let `T_(1) and T_(2)` be the TENSIONS in the strings OA and OB respectively According to lani.s THEOREM `(T_(1))/(sin90^(0))=(T_(2))/(sin150^(0))=(W)/(sin120^(0))(T_(2)30N)` on SOLVING w = `30sqrt(3)N` and `T_(1)`=60N |
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