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In the given figure, two rays BD and CE intersect at a point A. The side BC of ∆ABC have been produced on both sides to points F and G respectively. If ∠ABF = x°, ∠ACG = y° and ∠DAE = z° then z = ?(a) x + y – 180(b) x + y + 180(c) 180 – (x + y)(d) x + y + 360° |
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Answer» In the given figure, two rays BD and CE intersect at a point A. The side BC of ∆ABC have been produced on both sides to points F and G respectively. If ∠ABF = x°, ∠ACG = y° and ∠DAE = z° then z = ? (a) x + y – 180 (b) x + y + 180 (c) 180 – (x + y) (d) x + y + 360°
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