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In the given figure, x equals(a) \(\frac{ab}{a+c}\)(b) \(\frac{ac}{a+b}\)(c) \(\frac{ac}{b+c}\)(d) \(\frac{ab}{b+c}\) |
Answer» (c) \(\frac{ac}{b+c}\) In Δs LMK and ONK, ∠KML = ∠ONK = 46° ∠K = ∠K (Common) ∴ ΔLMK ~ ΔONK (AA similarity) ⇒ \(\frac{KM}{KN}=\frac{LM}{ON}⇒\frac{b+c}{c} =\frac{a}{x}⇒x=\frac{ac}{b+c}\). |
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