In the given reaction, C6H6 + Br2 → C6H5Br + HBr39 g of C6H6 reacts – InterviewSolution

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1.	In the given reaction, C6H6 + Br2 → C6H5Br + HBr39 g of C6H6 reacts with 40 g of Br2. It was found that 19.625 g of C6H5Br was obtained. Calculate the percentage yield of the reaction.(Given, Molar mass of: C6H6=78 g mol−1, Br2=160 g mol−1, C6H5Br=157 g mol−1)
Answer» In the given reaction, $C_{6} H_{6} + B r_{2} \to C_{6} H_{5} B r + H B r$ $39 g$ of $C_{6} H_{6}$ reacts with $40 g$ of $B r_{2}$ . It was found that $19.625 g$ of $C_{6} H_{5} B r$ was obtained. Calculate the percentage yield of the reaction. $(Given, Molar mass of: C_{6} H_{6} = 78 {g mol}^{- 1}, B r_{2} = 160 {g mol}^{- 1}, C_{6} H_{5} B r = 157 {g mol}^{- 1})$

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