In the given reactionC6H5−O||C−O||C−C6H5(i)CH3MgBr(excess)(iii)HOH/HProductProduct will be: (a) C6H5C−OH|C|CH3−OH|C|CH3−C6H5 (b) C6H5C−OH|C|CH3−O|C−C6H5(c) C6H5−COOH(d) C6H5−CHOH−CHOH−C6H5

In the given reactionC6H5−O||C−O||C−C6H5(i)CH3MgBr(excess)(iii)H

1.	In the given reactionC6H5−O\|\|C−O\|\|C−C6H5(i)CH3MgBr(excess)(iii)HOH/HProductProduct will be: (a) C6H5C−OH\|C\|CH3−OH\|C\|CH3−C6H5 (b) C6H5C−OH\|C\|CH3−O\|C−C6H5(c) C6H5−COOH(d) C6H5−CHOH−CHOH−C6H5
Answer» In the given reaction $C_{6} H_{5} - O \| \| C - O \| \| C - C_{6} H_{5} \frac{(i) C H_{3} M g B r (e x c e s s)}{(i i i) H O H / H} P r o d u c t$ Product will be: $(a) C_{6} H_{5} C - O H \| C \| C H_{3} - O H \| C \| C H_{3} - C_{6} H_{5}$ $(b) C_{6} H_{5} C - O H \| C \| C H_{3} - O \| C - C_{6} H_{5}$ $(c) C_{6} H_{5} - C O O H$ $(d) C_{6} H_{5} - C H O H - C H O H - C_{6} H_{5}$